I wrote one query as below to get latest orders for each client. It returns the first value in an ordered set of values. This query will get the first 10 records. Merge the temporary extents back to get the first 10 records when they are requested. I tried using OVER PARTITION BY clause, but somehow I'm not getting the desired result :select row_number() OVER(PARTITION BY leafv , value_group , l1d ,l2d ,l3d ,l4d ,l5d ,l6d ,l7d order by leafv , value_group , This setting is useful for data densification. Something like this can also indicate the first and last rows as you query... SQL> select empno, ename, hiredate 2 ,case row_number() over (order by hiredate) 3 when 1 then 'First Row' 4 when count(*) over then 'Last Row' 5 end as flag 6 from emp; EMPNO ENAME HIREDATE FLAG ----- ----- ----- ----- 7369 SMITH 17/12/1980 00:00:00 First Row 7499 ALLEN 20/02/1981 00:00:00 7521 WARD … Without the NO_WAIT parameter, Oracle Forms keeps trying to obtain a lock without letting the operator cancel the process. When you use NO_WAIT, Oracle Forms displays a dialog to notify the operator if a record cannot be reserved for update immediately. Contribute your code (and comments) through Disqus. The important point here is that it uses a subquery to do the ordering first, and then the outer query performs the rownum limiting. Have another way to solve this solution? How to get the top value from a table. Clean up (release) the temporary extents as you are finished with them. How to Write an Oracle Pagination Query Answer: To retrieve the Top N records from a query, you can use the following syntax: SELECT * FROM (your ordered query) alias_name WHERE rownum <= Rows_to_return ORDER BY rownum; For example, if you wanted to retrieve the first 3 records from the suppliers table, sorted by supplier_name in ascending order, you would run the following query: If the first value in the set is null, then the function returns NULL unless you specify IGNORE NULLS. Here is what we're going to explain. The rownum is assigned after the ORDER BY because it’s in the outer query. Internal query works fine. The first approach is to use an embedded select. Oracle Database has most likely copied the entire table into TEMP and written it out, just to get the first 10 rows. You could change this query to suit your needs. Different SQL syntax for Oracle 8i, 9i, 10g, 11g, and above. Now, that is a lot of I/O. My requirement is to get each client's latest order, and then get top 100 records. Previous: Write a query to check if the first_name fields of the employees table contains numbers Next: Write a query to get monthly salary (round 2 decimal places) of all employees. And in the main query I have a condition to only include rows where the rank is equal to 1, which will give me all of the employees who earn the smallest bonus in each department, and then I group by department id to get the count of rows for each department. There are at least two different approaches which can be taken to return the first record in a group - in our working example the date when each page was first viewed and the IP address associated with that event. SQL to return the first record in a group. This is a variant of a top-1 query, as you may have noticed. ORACLE Query to return First Row for a DataSet I'm writing a query which would return first row of a set of grouped data. 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